Question

One alloy corains 60% of gold; another contains 80% of goll A new alloy is made of 2 parts of the first to 3 parts of the secoul How much percent affbe misture is gold​

Answer 1

Answer:

Initial quantity of Gold = 50 * 80% = 50 * 80/100 = 40 gms. So, initial quantity of Silver = 50 - 40 = 10 gms.

Now, if only Gold is added to make percentage of Gold increased to 90% then, Silver remains at 10 gms only. In final quantity, Silver percentage is 100 - 90 = 10%. Hence, total quantity of alloy metal = 10/ 10% = 10 * 100/10 = 100 gms. So, in the final alloy, quantity of Gold = 100 -10 = 90 gms. Hence, Gold to be added = 90 - 40 = 50 gms Ans.