Math, asked by VijayaLaxmiMehra1, 1 year ago

One alloy of iron is 49% iron and another 28% iron. How many tons of each should be to make 120 tons of 42% iron alloy?

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Answered by nikky28
22
HELLO. !!!.....


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An alloy of iron is 49% iron and other is 28% of iron.How many kilogram of each should be used to get 120 kg of 42%iron alloy?

Let x kg of 49% iron alloy is used 

and y kg of 28% iron alloy  is used.

therefore, acc. to the question,

x + y = 120. - - - - - - - (1)

and \:  \frac{49}{100} x +  \frac{28}{100} y =  \frac{42}{100}    \times 120 \\  \\  =  > 7x + 4y = 720 \:  \:  \:  \:  \:  -  -  -  -  -  - (2)

●on multiplying (i) by 4 and subtracting from (ii) , we get,

3x= 240 

==> x= 80

put in (i), we get,

80+y=120

y=12080

==> y=40

●thus, 80 kg of 49% iron alloy is used  and 40 kg of 28% iron alloy  is used.


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HOPE IT HELPS U DEAR! !!!

# NIKKY

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GOOD NIGHT :))

VijayaLaxmiMehra1: :-)
Answered by Satyamrajput
4
Heya......✋
Answer is in attachment.....
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