Question

One ampere of current is passed for 9650 seconds through molten AlCl3 . What is the weight in grams of Al deposited at cathode?(atomic weight of Al =27

Answer 1

Hey Dear,

◆ Answer -

Aluminum deposited = 0.9 g

◆ Explaination -

Reaction for electrolysis of molten AlCl3 is -

2 AlCl3 --> 2 Al+ + 3 Cl2

Number of moles of aluminum deposited are calculated by -

Aluminum deposited = Equivalent mass × current / 96500

Aluminum deposited = 27/3 × 9650 / 96500

Aluminum deposited = 0.9 g

Hence, aluminum deposited at cathode is 0.9 g after passing current through it.

Thanks for asking. Hope this helps you...