one angle of a parallelogram is 100 degree find the measure of the remaining three angles
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Let's say ABCD is a parallelogram.
Angle A= 100 degree
Angle C= Angle A (Opposite angle of parallelogram is equal)
Thus, Angle C= 100 degree
Now, we know that opposite sides of parallelogram are parallel.
So, Angle A + Angle D= 180 degree (co-interior angle; when a transversal passes through two parallel line the angle on same side of the transversal i.e co-interior angles is equal to 180 degree )
Angle D= 80 degree
Similarly,
Angle
Angle C + Angle B = 180 degree (co-interior angle)
Angle B= 80 degree
Thus, Angle A= 100 degree
Angle B= 80 degree
Angle C= 100 degree
Angle D= 80 degree
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