One angle of a parallelogram is 12 less than 5 times the measure of the adjacent angle. What are the measures of these angles?
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28
let one angle be X
so, other angle be 5x-12
ATQ
X+5x-12=180
6x=180-12
6x=168
X=168/6
hence X=28
now,one angle=28
other angle is 5×28-12
= 140-12.
= 128
so, other angle be 5x-12
ATQ
X+5x-12=180
6x=180-12
6x=168
X=168/6
hence X=28
now,one angle=28
other angle is 5×28-12
= 140-12.
= 128
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