one angle of a parallelogram is 45° more than its adjacent angle. Find the angles of the parallelogram. Do step by step
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Answer:
let the adjacent angle be x°
one angle=x+45°
let angle a=x° and angle b =x+45°
we know that adjacent angles of parallelogram are supplementary
thus
x+x+45° =180°
2x=180-45°
2x=135°
x=135/2°
x=67.5°
thus angle a is 67.5° .
thus angle b=x+45°
=67.5+45°
=112.5°
angle b = angle d = 112.5° [ opposite angles are equal in parallelogram]
angle c = angle a =67.5° [opposite angles are equal in parallelogram].
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