One angle of a parallelogram is 80 find tha measures of other three angles.
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Answered by
10
Let the other angle be x
We know that the opposite angle are equal in a parallelogram
=> angle opposite to 80° will also be 80°
and => angle opposite to x will also be x
So the angles are
80°, x, 80°, x
By angle sum property,
80° + x + 80° + x = 360°
=> 2x + 160° = 360°
=> 2x = 360 - 160
=> 2x = 200°
=> x = 200/2
=> x = 100°
So the unknown angle is 100°
Since opposite angles are equal, the all four angles are :-
80°, 100°, 80° and 100°
Hope it helps dear friend ☺️✌️
We know that the opposite angle are equal in a parallelogram
=> angle opposite to 80° will also be 80°
and => angle opposite to x will also be x
So the angles are
80°, x, 80°, x
By angle sum property,
80° + x + 80° + x = 360°
=> 2x + 160° = 360°
=> 2x = 360 - 160
=> 2x = 200°
=> x = 200/2
=> x = 100°
So the unknown angle is 100°
Since opposite angles are equal, the all four angles are :-
80°, 100°, 80° and 100°
Hope it helps dear friend ☺️✌️
BrainlyQueen01:
Great Answer (^o^)
Answered by
1
∵ Opposite angles in parallelogram are equal
∴ the measure os its opposite angle will be 80
∵all angles measure 360
∴the measure of other two angles = 360-2*80 /2
= 360-160/2
=200/2
=100
hence, 100, 100 and 80 are the measure of other three angles
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