Question

One angle of a parallelogram is 85 degree find the amazing of the remaining angle of the parallelogram

Answer 1

Step-by-step explanation:

Opposite to 85° angle is also 85°

Adjacent two angle = 180° - 85°

= 95°

Answer 2

Step-by-step explanation:

Let ABCD be a parallelogram with Angle A = 85°; Angle C = Angle A.

Let ABCD be a parallelogram with Angle A = 85°; Angle C = Angle A.Angle A + Angle B + Angle C + Angle D = 360°

Let ABCD be a parallelogram with Angle A = 85°; Angle C = Angle A.Angle A + Angle B + Angle C + Angle D = 360°(Opposite angles of a parallelogram are equal)

Let ABCD be a parallelogram with Angle A = 85°; Angle C = Angle A.Angle A + Angle B + Angle C + Angle D = 360°(Opposite angles of a parallelogram are equal)85°+ Angle B + Angle 85°+ Angle D = 360°

Let ABCD be a parallelogram with Angle A = 85°; Angle C = Angle A.Angle A + Angle B + Angle C + Angle D = 360°(Opposite angles of a parallelogram are equal)85°+ Angle B + Angle 85°+ Angle D = 360°Angle B + Angle D + 170° = 360°

Let ABCD be a parallelogram with Angle A = 85°; Angle C = Angle A.Angle A + Angle B + Angle C + Angle D = 360°(Opposite angles of a parallelogram are equal)85°+ Angle B + Angle 85°+ Angle D = 360°Angle B + Angle D + 170° = 360°(Angle sum property of a quadrilateral)

Let ABCD be a parallelogram with Angle A = 85°; Angle C = Angle A.Angle A + Angle B + Angle C + Angle D = 360°(Opposite angles of a parallelogram are equal)85°+ Angle B + Angle 85°+ Angle D = 360°Angle B + Angle D + 170° = 360°(Angle sum property of a quadrilateral)Angle B + Angle D = 360° - 170° = 190° .... (1)

Let ABCD be a parallelogram with Angle A = 85°; Angle C = Angle A.Angle A + Angle B + Angle C + Angle D = 360°(Opposite angles of a parallelogram are equal)85°+ Angle B + Angle 85°+ Angle D = 360°Angle B + Angle D + 170° = 360°(Angle sum property of a quadrilateral)Angle B + Angle D = 360° - 170° = 190° .... (1)But, Angle B = Angle D

Let ABCD be a parallelogram with Angle A = 85°; Angle C = Angle A.Angle A + Angle B + Angle C + Angle D = 360°(Opposite angles of a parallelogram are equal)85°+ Angle B + Angle 85°+ Angle D = 360°Angle B + Angle D + 170° = 360°(Angle sum property of a quadrilateral)Angle B + Angle D = 360° - 170° = 190° .... (1)But, Angle B = Angle D (Opposite angles of a parallelogram are equal)

Let ABCD be a parallelogram with Angle A = 85°; Angle C = Angle A.Angle A + Angle B + Angle C + Angle D = 360°(Opposite angles of a parallelogram are equal)85°+ Angle B + Angle 85°+ Angle D = 360°Angle B + Angle D + 170° = 360°(Angle sum property of a quadrilateral)Angle B + Angle D = 360° - 170° = 190° .... (1)But, Angle B = Angle D (Opposite angles of a parallelogram are equal)=》From Equation ( 1 )

Let ABCD be a parallelogram with Angle A = 85°; Angle C = Angle A.Angle A + Angle B + Angle C + Angle D = 360°(Opposite angles of a parallelogram are equal)85°+ Angle B + Angle 85°+ Angle D = 360°Angle B + Angle D + 170° = 360°(Angle sum property of a quadrilateral)Angle B + Angle D = 360° - 170° = 190° .... (1)But, Angle B = Angle D (Opposite angles of a parallelogram are equal)=》From Equation ( 1 )Angle B + Angle B = 190°

Let ABCD be a parallelogram with Angle A = 85°; Angle C = Angle A.Angle A + Angle B + Angle C + Angle D = 360°(Opposite angles of a parallelogram are equal)85°+ Angle B + Angle 85°+ Angle D = 360°Angle B + Angle D + 170° = 360°(Angle sum property of a quadrilateral)Angle B + Angle D = 360° - 170° = 190° .... (1)But, Angle B = Angle D (Opposite angles of a parallelogram are equal)=》From Equation ( 1 )Angle B + Angle B = 190°2 Angle B = 190°

Let ABCD be a parallelogram with Angle A = 85°; Angle C = Angle A.Angle A + Angle B + Angle C + Angle D = 360°(Opposite angles of a parallelogram are equal)85°+ Angle B + Angle 85°+ Angle D = 360°Angle B + Angle D + 170° = 360°(Angle sum property of a quadrilateral)Angle B + Angle D = 360° - 170° = 190° .... (1)But, Angle B = Angle D (Opposite angles of a parallelogram are equal)=》From Equation ( 1 )Angle B + Angle B = 190°2 Angle B = 190° Angle B = 190°/2 = 95°

Let ABCD be a parallelogram with Angle A = 85°; Angle C = Angle A.Angle A + Angle B + Angle C + Angle D = 360°(Opposite angles of a parallelogram are equal)85°+ Angle B + Angle 85°+ Angle D = 360°Angle B + Angle D + 170° = 360°(Angle sum property of a quadrilateral)Angle B + Angle D = 360° - 170° = 190° .... (1)But, Angle B = Angle D (Opposite angles of a parallelogram are equal)=》From Equation ( 1 )Angle B + Angle B = 190°2 Angle B = 190° Angle B = 190°/2 = 95°So, Angle B = Angle D = 95° and Angle A = Angle C = 85°

Let ABCD be a parallelogram with Angle A = 85°; Angle C = Angle A.Angle A + Angle B + Angle C + Angle D = 360°(Opposite angles of a parallelogram are equal)85°+ Angle B + Angle 85°+ Angle D = 360°Angle B + Angle D + 170° = 360°(Angle sum property of a quadrilateral)Angle B + Angle D = 360° - 170° = 190° .... (1)But, Angle B = Angle D (Opposite angles of a parallelogram are equal)=》From Equation ( 1 )Angle B + Angle B = 190°2 Angle B = 190° Angle B = 190°/2 = 95°So, Angle B = Angle D = 95° and Angle A = Angle C = 85° Thanks☺