Question

One angle of a parallelogram is of measure 70°. Find the measures of the remaining angles of the parallelogram.

pls fast

Answer 1

Answer:

70° , 110° , 110°.

Step-by-step explanation:

In a parallelogram, two angles are equal to each other, whereas in the same manner other( remaining ) two angles are equal to each other.

Here,

One given angle is 70°, so in that parallelogram there must be an another angle of 70°.

Let the other two equal angles are of angle-measure a.

= > Sum of all angles( at vertices ) = 360°

= > 70° + 70° + a + a = 360°

= > 140° + 2a = 360°

= > 2a = 360° - 140°

= > 2a = 220°

= > a = 110°

Hence other two angles are 110° and 110°.

Answer 2

Answer:

⋆ Given :

• One Angle of Parallelogram = 70°

⋆ To Find :

• Find other Angles.

⋆ Solution :

• We know the Property of Parallelogram, that the Opposite Angle of Parallelogram are Equal, so there will be Another 70° Angle.
• & Another Two Angles will be Opposite to each other and equal.
• Sum of All Sides of Parallelogram is equal to 360°

Let the Other Two Angles be x°

☯ According to the Question :

↠ ∠ 1 + ∠ 2 + ∠ 3 + ∠ 4 = 360°

↠ 70° + x + 70° + x = 360°

↠ 2x + 140° = 360°

↠ 2x = 360° – 140°

↠ 2x = 220°

• Dividing both term by 2

↠ x = 110°

∴ Other Angles of ||gram are 110° & 110°.