One angle of a parallelogram is of measure 70° find the measure
of the remaining angles of the parallelogram.
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15
Answer:
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120-10= 110 degree. The sum of the angles of a parallelogram is 360 degrees. At least two angles will be the same unless one angle is of measure 90 degrees (in which case all four are 90). Hence, the remaining angles are 70 degrees and 2 110 degree angles.
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Answered by
27
Answer:
If we take a parallelogram ABCD.
∠A =70°
∠C=70° [∵Opposite angles]
As ∠A and ∠B are adjacent angles, their sum will be equal to 180°.
So, ∠A + ∠B = 180°
∠B = 180°-70°
∠B = 110°
∠B = ∠D [∵Opposite angles]
∠D = 110°
∴ Angles of given parallelogram are 70°,110°,70°,110°.
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