Question

One angle of a parallelogram is two-third of the other. Find the angles of the
parallelogram. ​

Answer 1

Answer:

240 °

x+x+x+240= 360

3x=360-240

3x = 120

x = 120/3

=40° each

40°,40°,40°,240°

Answer 2

Given:-

• One angle of a Parallelogram is two - third of the other.

To Find:-

• The angles of the Parallelogram.

Concept Used:-

• In Parallelogram Opposite angles are equal

• Sum of two Consecutive angles of Parallelogram is 180°

Now,

→ Let the angles be "x".

then,

→ Second angle =$\rm{\dfrac{2}{3}x}$.

→ $\rm{ x + \dfrac{2}{3}x = 180^{\circ}}$

→ $\rm{ \dfrac{3x + 2x}{3} = 180^{\circ}}$

→ $\rm{5x = 180 * 3}$

→ $\rm{ 5x = 540}$

→ $\rm{ x = \dfrac{540}{5}}$

→ $\rm{ x = 108^{\circ}}$.

So, First angle = 108°

Second angle = ⅔ × 108 → 36 × 2 → 72°.

So, Using thee Concept given above.

The angles area 108° , 72° , 108° and 72°