One angle of a pentagon is 140∘140∘. if the remaining angles are in the ratio 1:2:3:4, find the size of the greatest angle.
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Answered by
12
THE SUM OF ALL ANGLES IN A PENTAGON IS 540
140+x+2x+3x+4x=540
10x=540-140
x=400/10
x=40
x=40
2x=2*40=80
3x=3*40=120
4x=4*40=160
THE GREATEST ANGLE IS 160=4x
140+x+2x+3x+4x=540
10x=540-140
x=400/10
x=40
x=40
2x=2*40=80
3x=3*40=120
4x=4*40=160
THE GREATEST ANGLE IS 160=4x
Answered by
9
Answer:160
Step-by-step explanation:
number of sides of a pentagon=5
(n-2)180
(5-2)×180
3×180
540
Let the angles ne x 2x 3x 4x
Then
x +2x +3x +4x+140=540
x +2x +3x +4x=540-140
x +2x +3x +4x=400
10x=400
x=40
Greatest angle =4x=4(40)=160
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