one angle of a pentagon is 160 degree. Find each of the other equal angles. (ans=95 degree) want the solution...asap!!
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We know that -
The sum of interior angles of a any polygon having n sides = (n-2)*180
for pentagon,
n = 5
So, the sum of interior angles of a any pentagon = (5-2)*180
= 3*180
= 540 degrees.
Now one angle of the pentagon is 160 degrees (given)
So,
The remaining angles = 540 degrees - 160 degrees
= 380 degrees
Now the remaining 4 angles are equal. So, We need to divide the total remaining angles by 4:
Hence each angle = 380 degrees / 4
= 95 degrees.
The sum of interior angles of a any polygon having n sides = (n-2)*180
for pentagon,
n = 5
So, the sum of interior angles of a any pentagon = (5-2)*180
= 3*180
= 540 degrees.
Now one angle of the pentagon is 160 degrees (given)
So,
The remaining angles = 540 degrees - 160 degrees
= 380 degrees
Now the remaining 4 angles are equal. So, We need to divide the total remaining angles by 4:
Hence each angle = 380 degrees / 4
= 95 degrees.
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