One angle of a pentagon measures 80°. The other four angles are equal in measure. Find the measure of one of the equal angles
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MEASURE OF FIRST ANGLE OF PENTAGON = 80°
IF ALL ANGLES R EQUAL... THEN LET THEY R EQUAL TO = X°
.
WE KNOW THAT ,
SUM OF ALL ANGLES OF PENTAGON =540°
SO, 80° + X + X + X + X =540°
80+4X = 540°
4X= 540-80
4X =460
X = 460/4
X=115° .....
THNK U
IF ALL ANGLES R EQUAL... THEN LET THEY R EQUAL TO = X°
.
WE KNOW THAT ,
SUM OF ALL ANGLES OF PENTAGON =540°
SO, 80° + X + X + X + X =540°
80+4X = 540°
4X= 540-80
4X =460
X = 460/4
X=115° .....
THNK U
Ayushbhatia3542:
Thanks bro!!
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One angle of a pentagon measures 80°. The other four angles are equal in measure. Find the measure of one of the equal anglesOne angle of a pentagon measures 80°. The other four angles are equal in measure. Find the measure of one of the equal anglesOne angle of a pentagon measures 80°. The other four angles are equal in measure. Find the measure of one of the equal angles
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