One angle of a quadrilateral is 60° and the remaining three interior angles are equal. Find the measure of each of the remaining angles.
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Given one angle is 60° and the remaining 3 interior angles are equal.
Let ∠D = 60° and ∠A = ∠B = ∠C be x
We know that the sum of interior angles of quadrilateral is 360°
So ∠A + ∠B + ∠C + ∠D = 360°
x + x + x + 60° = 360°
3x + 60° = 360°
3x = 360° - 60°
3x = 300°
x = 300°/3
x = 100°
Therefore ∠A = ∠B = ∠C = 100°
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Given one angle is 60° and the remaining 3 interior angles are equal.
Let ∠D = 60° and ∠A = ∠B = ∠C be x
We know that the sum of interior angles of quadrilateral is 360°
So ∠A + ∠B + ∠C + ∠D = 360°
x + x + x + 60° = 360°
3x + 60° = 360°
3x = 360° - 60°
3x = 300°
x = 300°/3
x = 100°
Therefore ∠A = ∠B = ∠C = 100°
Mark me as brainliest ;)
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