One angle of a quadrilateral is twice the other and rest two angles are given as 35 degree and 105 degree find the remaining two angles of the quadrilateral
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✰✰|| Given ||✰✰
- one angel of quadrilateral is twice other
- rest two angels = 35° and 105°
✰✰|| To Find ||✰✰
- remaining two angels of quadrilateral
✪|| Solution ||✪
Let, the other angel be x
Sum of all angle of quadrilateral = 360°
2x + x + 35° + 105° = 360°
3x + 140° = 360°
3x = 360° - 140°
3x = 220°
x = 220°/3
x = 71.42
1st angel of quadrilateral = 2x
→ 1st angel of quadrilateral = 2 × 71.42
→ 1st angel of quadrilateral = 142.84
2nd angel of quadrilateral = x
→ 2nd angel of quadrilateral = 71.42
1st angel of quadrilateral is
142.84° and 2nd angel of
quadrilateral is 71.42°
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