Question

one angle of a rhombus is 50 degree and the larger diagonal is 5cm what is it's area?​

Answer 1

A=pq/2 is the formula

Answer :

Solving forp

p=2A

q=2·5

50=0.2

Answer 2

ANSWER:

Given:

•One angle of a rhombus is 50°.

•The larger diagonal is 5cm.

To find:

Area of a rhombus.

Solution:

In a rhombus, (ABCD);

Let DB= 5cm

angle ADC= 50°

We know that,

•Diagonal of a rhombus are perpendicular bisector to each other.

•Diagonals bisect the corner angles of rhombus.

Therefore,

•angle ODC= 25° [DB bisects angle D]

OD= 2.5cm [AC bisect BD]

OC is given by;

OC = OD × tan25°

OC = 2.5 × 0.466

OC = 1.166cm

&

AC = 2 × OC [BD bisect AC]

AC= 2 × 1.166

AC= 2.332cm

Now,

Area of rhombus:

=) 1/2 × d1 × d2

=) 1/2 × AC × BD

=) 1/2 × 2.332 × 5

=) 11.66/2

=) 5.83cm²

Thus,

The area of rhombus is 5.83cm².

Thank you.