Question

One angle of a triangle has measure 2pie/9 and the measures of the other two angles are in ratio 4:3, find their measures in degrees and radians.

Answer 1

Hello friend! I am glad to help you. Here is the answer.


We know that, 1radian = (180/pie)°
Therfore, 2pie/9 = (2pie9 × 180/pie)° = 40°

Let ABC be the triangle, such that measure of angle A = 2pie/9 = 40°.

The other two angles, i.e, angle B and angle C are in the ratio 4:3.

Let me sure of angle B=4k and C = 3k

Since, angle A + angle B + angle C = 180°
Therefore, 40° + 4k + 3k = 180°
7k = 140°
k = 20°

Therefore, Angle B = 4k = 4 ×*20 = 80°

Angle C = 3k × 20 = 60°

Now,
1° = ( pie/180)radian
Therfore, 80° = (80 × pie/180) = (4pie/9) radian
And
60° = ( 60 × pie/180) = pie/3 radian.


Hence, the measures of the other two angles are 80°, 60° or 4pie/9 radian and pie/3 radian.




Hope it helps you.

Answer 2

Answer:

i hope you will satisfy from my answer