One angle of a triangle is 120° and it's opposite side 3cm . Find the diameter of its circumcircle.
No need of irrelevant answers...
Answers
Step-by-step explanation:
Let ABCD be the given parallelogram.
DC = 6 cm and ∠ADC = 60°
Area of parallelogram ABCD = 30 cm2
Construction: Draw AE perpendicular to DC.
Area of a parallelogram = Base × Height
⇒ 30 cm2 = 6 cm × AE
⇒ AE =
Using angle sum property in ΔAED:
∠ADE + ∠DEA + ∠EAD = 180°
⇒ 60° + 90° + ∠EAD = 180°
⇒ 150° + ∠EAD = 180°
⇒ ∠EAD = 180° − 150° = 30°
Thus, the angles of ΔAED are 30°, 60° and 90°.
Therefore, the ratio of the lengths of the sides of ΔAED is 1::2.
Thus, the length of other side of the parallelogram is cm.
Note: We can also draw the figure by taking ∠ADE = 60° and AD = 6 cm.
Answer:
Step-by-step explanation:
Let ABCD be the given parallelogram.
DC = 6 cm and ∠ADC = 60°
Area of parallelogram ABCD = 30 cm2
Construction: Draw AE perpendicular to DC.
Area of a parallelogram = Base × Height
⇒ 30 cm2 = 6 cm × AE
⇒ AE =
Using angle sum property in ΔAED:
∠ADE + ∠DEA + ∠EAD = 180°
⇒ 60° + 90° + ∠EAD = 180°
⇒ 150° + ∠EAD = 180°
⇒ ∠EAD = 180° − 150° = 30°
Thus, the angles of ΔAED are 30°, 60° and 90°.
Therefore, the ratio of the lengths of the sides of ΔAED is 1::2.
Thus, the length of other side of the parallelogram is cm.
Note: We can also draw the figure by taking ∠ADE = 60° and AD = 6 cm.