Question

One angle of a triangle is 2/3 of a right angle. If the greater of other two is double of the smaller angle, find each angle in degrees.​

Answer 1

Answer:

Let the measure of the two angles be 2x and 3x (Since angles are in the ratio 2:3)

According to question,

2x+3x+90°=180°

5x=180°−90°

5x=90

x=

5

90

x=

5

90

x=18

∴ one angle is 2x=2×18=36°, second angle is 3x=3×18=54° and the third one is 90° as it is a right angled triangle.