one angle of a triangle is 60degree. the other two angles are in the ratio of 5:7 find the two angles
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Answered by
4
Let the common ratio be x
Therefore,the two angles are 5x and 7x
Now,
60degree+5x+7x=180degree (angle sum property of triangle)
5x+7x=180-60
12x =120degree
x= 120degree/12
x=10 degree
Therefore,the two angles are 5x=5×10=50 degree and
7x=7×10=70 degree
Therefore,the two angles are 5x and 7x
Now,
60degree+5x+7x=180degree (angle sum property of triangle)
5x+7x=180-60
12x =120degree
x= 120degree/12
x=10 degree
Therefore,the two angles are 5x=5×10=50 degree and
7x=7×10=70 degree
Answered by
3
Let one angel= 5x
other= 7x
So,
By Angle sum property of a ∆ we have,
60 + 5x + 7x =180
12x= 120
x= 10
➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖
therefore,
Other two angles of ∆ :--
Angle one= 5x= 50°
Angle two= 7x= 70°
other= 7x
So,
By Angle sum property of a ∆ we have,
60 + 5x + 7x =180
12x= 120
x= 10
➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖
therefore,
Other two angles of ∆ :--
Angle one= 5x= 50°
Angle two= 7x= 70°
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