Question

One angle of a triangle is 61 degree and the other two angles are in ratio 3/2: 4/3. Find these angles
​

Answer 1

Answer:rom the triangle ABC

Consider ∠A=61

∘

In a triangle

∠A+∠∠B+∠C=180

∘

Substituting the values

61

∘

+∠B+∠C=180

∘

By further calculation

∠B+∠C=180

∘

–61

∘

=119

∘

∠B:∠C=1

2

1

​

:1

3

1

​

=3/2:4/3

Taking LCM

∠B:∠C=9:8/6

∠B:∠C=9:8

Consider ∠B=9x and ∠C=8x

Substituting the values

9x+8x=119

∘

17x=119

∘

x=119

∘

/17=7

∘

So we get

∠B=9x=9×7

∘

=63

∘

∠C=8x=8×7

∘

=56

∘rom the triangle ABC

Consider ∠A=61

∘

In a triangle

∠A+∠∠B+∠C=180

∘

Substituting the values

61

∘

+∠B+∠C=180

∘

By further calculation

∠B+∠C=180

∘

–61

∘

=119

∘

∠B:∠C=1

2

1

​

:1

3

1

​

=3/2:4/3

Taking LCM

∠B:∠C=9:8/6

∠B:∠C=9:8

Consider ∠B=9x and ∠C=8x

Substituting the values

9x+8x=119

∘

17x=119

∘

x=119

∘

/17=7

∘

So we get

∠B=9x=9×7

∘

=63

∘

∠C=8x=8×7

∘

=56

∘

Step-by-step explanation: