One angle of a triangle is 61° & the.other two angles are in the ratio 1 1/2 : 1 1/3. Find the two angles.
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(You can draw a triangle for reference if you want)
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Given : angle A = 61°
let us consider angle B : angl C as 1 1/2 : 1 1/3.
=> B/C = (1 1/2)/ (1 1/3)
=> B/C = (3/2)/(4/3)
=> B/C = (3/2)×(3/4)
=> B/C = 9/8
=> B = (9/8)C ----------------(1)
A+B+C = 180° {angle sum property }
61 + (9/8)C + C = 180
(9/8)C + C = 180-61
(9C + 8C)/8 = 119
17C = 119×8
C = 952/17
C = 56
B = (9/8)C
B = (9/8)56
B = 9×7
B = 63
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