Question

one angle of a triangle is 65 degree.Find the remaining two angles if their difference is 20 degree

Answer 1

let the bigger angle be x
65+x+x-20=180 (angle sum property)
2x+65-20=180
2x+65=180+20
2x+65=200
2x=200-65
2x=135
x=2√135
x=65.5

Answer 2

Answer:

$Required \:two \: angles \: of \: triangle \:are\\67.5 \: and \: 47.5$

Step-by-step explanation:

Let x ,y and z are three angles of a triangle .

/* According to the problem given,

Let x = 65° , y-z = 20 ---(1)

x + y + z = 180° /* Angle sum property */

=> 65° + y + z = 180°

=> y + z = 180° - 65°

=> y + z = 115° ---(2)

/* Add equations (1) and (2) , we get

2y = 135°

$\implies y = \frac{135}{2}$

$\implies y = 67.5$

/* Substitute y = 67.5 in equation (2) ,we get

$67.5 + z = 115$

$\implies z = 115 - 67.5 = 47.5$

Therefore.,

$Required \:two \: angles \: of \: triangle \:are\\67.5 \: and \: 47.5$

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