- One angle of a triangle is 65º. Find the remaining two angles if their difference is 20
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Angle A = 65
Angle B = x
Angle C = x + 20
Therefore we have
65 + x + x + 20 = 180
85+ 2x = 180
2x = 180 - 85
= 95
2x = 95
x = 95/2
= 47.5
Therefore angle B is 47.5 degree
Angle C = x + 20
= 47.5 + 20
= 67.5
Angle C = 67.5 degree
Angle B = x
Angle C = x + 20
Therefore we have
65 + x + x + 20 = 180
85+ 2x = 180
2x = 180 - 85
= 95
2x = 95
x = 95/2
= 47.5
Therefore angle B is 47.5 degree
Angle C = x + 20
= 47.5 + 20
= 67.5
Angle C = 67.5 degree
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