Question

One angle of a triangle is 78degree and the other angles are in the ratio 7:10.find their measures​

Answer 1

Answer:

Step-by-step explanation:Let ABC be the triangle such that angle A is 60

o

.

In addition, let angle B and C are x and 2x respectively.

∠A+∠B+∠C=180

o

⇒ 60

o

+x+2x=180

o

⇒ 3x=180

o

−60

o

⇒ x=

3

120

o

​

⇒ x=40

o

Therefore,

∴ ∠B=40

o

∠C=2×40

o

=80

o

So, other angles are 40

o

, 80

o

Answer 2

AnSwer : 42° & 60°

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E x P l a n a t i o n : Question states that one angle of a triangle is 78° and the Other angles of the triangle are in the ratio of 7 : 10. & we're asked to Calculate these angles.

Let the other two angles be 7x and 10x respectively.

Therefore,

• First angle = 7x

• Second angle = 10x

• Third angle = 78°

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✇ Now, According to the ASP ( Angle Sum ProPerty ) of the $\Delta$ Here:

★ ⠀∠X + ∠Y + ∠Z = 180°⠀ ⠀⠀[Angle Sum Property]

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⇥⠀7x + 10x + 78° = 180

⠀

⇥⠀17x = 180° – 78°

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⇥⠀17x = 102°

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⇥⠀ x = 102⁄17

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⇥⠀ x = 6°

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Therefore,

• First angle, 7(6) = 42°
• Second angle, 10(6) = 60°
• Third angle, 78°

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❝ Hence, the angles are 42°, 60° & 78° respectively. ❞