one angle of a triangle is double the first. the third angle is 40° less than the first. find the three angles of the triangle
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Answer:
let us a triangle ABC .
Let A = x (first angle)
And we have given ,
B = twice of first angle.
B = 2x. (second angle)
C = 40 less than the first angle.
C = x - 40. (third angle)
By using angle sum property we can find the three angles.
A + B + C = 180 .
x + 2x + x - 40 = 180.
4x - 40 = 180.
4x = 180+40.
x = 220/4.
x = 55.
So we have ..
A = 55.
B = 2*55 = 110.
C = 55–40 = 15.
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