one angle of a triangle is equal to the sum of the other two.If the ratio of the other two angles is 7:8,find the angles of the triangles
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The ratio between other two angles of a triangle is 7:8
So lets suppose one of the other two angle is 7x°.
That means the second angle between those angles is 8x°.
But since the first angle is the sum of the other two angles.
=> First angle = 7x° + 8x° = 15x°.
We know that the sum of angles of a triangle is always 180°.
=> 15x° + 7x° + 8x° = 180°
=> x = 6°
●So first angle = 15×6 = 90°
●Second angle = 7×6 = 42°
●Third angle = 8×6 = 48°
●●●Hope it Helps●●●
The ratio between other two angles of a triangle is 7:8
So lets suppose one of the other two angle is 7x°.
That means the second angle between those angles is 8x°.
But since the first angle is the sum of the other two angles.
=> First angle = 7x° + 8x° = 15x°.
We know that the sum of angles of a triangle is always 180°.
=> 15x° + 7x° + 8x° = 180°
=> x = 6°
●So first angle = 15×6 = 90°
●Second angle = 7×6 = 42°
●Third angle = 8×6 = 48°
●●●Hope it Helps●●●
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