One angle of a triangle is the sum of its other two angles.If one of these two angles is half of the third angle, find all the angles
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Let the angles be a,b,c..
a=b+c
b=1/2c
a=1/2c+c = 3/2c
a+b+c = 180
3/2c+1/2c+c = 180
3c=180
c=60
a=3/2*60=90
b=1/2*60= 30
c=60
a=b+c
b=1/2c
a=1/2c+c = 3/2c
a+b+c = 180
3/2c+1/2c+c = 180
3c=180
c=60
a=3/2*60=90
b=1/2*60= 30
c=60
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