Math, asked by harshitkumarjakhar2, 19 days ago

one angle of a triangle is twice the smallest angle and another angle is three times the smallest angle. find the measure of all the angles of triangle .​

Answers

Answered by kumarpankaj19309
3

Answer:

let the smallest angle=x

then other angles will be 2x and 3x.

sum of all three angles of a triangle=180°

then x+2x+3x=180°

6x=180°

x=30°

so all three angles will be 30°,60°and 90°

Answered by aftabahemad
2

In context to question asked,

We have to determine the value of measurement of angle of triangle.

As per question,

One angle of a triangle is twice the smallest angle and another angle is three times the smallest angle.

So, let the value of the smallest angle = x

So, the value of first angle will be twice the smallest angle =2\times x = 2x

And, the value of another angle will be three times the smallest angle =3\times x = 3x

As we know that,

Sum of all angles of the triangle = 180 degree.

So, from above,

We can rewrite it as,

x+2x+3x = 180^0\\=>6x = 180^0\\=>x = \frac{180}{6} = 30^0

Hence, value of all the angles will be,

1st \:angle = x = 30^0\\2nd \:angle = 2x = (2\times 30^0) = 60^0\\3rd \:angle = 3x =\times  30^0 = 90^0

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