One angle of parallelogram is 90° prove that remaining angles are also of 90°.
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Let,ABCD is a parallelogram.
Where angle BAC is 90 °.
we know,angle BAC+angle ABC=180°
or,angle ABC+90°=180°
or,angle ABC=90°
Therefore,angle ABC=angle ADC=90°
angle BAC=angle BDC=90°
So,if 1 angle of a parallelogram is 90° then the other angles are also 90°.
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