Math, asked by shrutiharry9382, 1 year ago

One angle of parallelogram is 90° prove that remaining angles are also of 90°.

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Answered by soumya3024
0

Let,ABCD is a parallelogram.

Where angle BAC is 90 °.

we know,angle BAC+angle ABC=180°

or,angle ABC+90°=180°

or,angle ABC=90°

Therefore,angle ABC=angle ADC=90°

angle BAC=angle BDC=90°

So,if 1 angle of a parallelogram is 90° then the other angles are also 90°.

Answered by Anonymous
1

Answer:

Pl see attachment

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