Question

One angle of parallelogram is of 90°.prove that all remain angle of parallelogram are also 90°

Answer 1

If one angle of a parallelogram is 90°

all the remaining angles will also be 90°

proof:

firstly a parallelogram is also a quadrilateral

and the corresponding angles of a quadrilateral is supplementary so in this way we can prove that all the angles of a parallelogram is supplementary.

hope it helps ✌️✌️

Answer 2

hey mate here is your answer:

Given :A llgm

with one angle of 90°

To prove: All angles =90°

Proof: Angle 1= angle 3 (opposite angles of llgm r equ)

=>Angle 2=90°

Now,

Angle 1 + angle 4=180° (interior angles on the same side of transversal)

angle 4=180°- angle 1

angle 4 =180°-90°f

angle 4 =90°

angle 4=angle 2(opposite angles of llgm)

=>angle 2=90°

there fore ,

angle 1=angle 3=angle 2=angle 4=90°

Hence,proved.

hope it helps you