Question

one angle of triangle ABC is 40°. If the difference of the other two angles is 30°, find the larger of the other two angles. *

Answer 1

Answer:

The value of the larger angle is 85°.

Step-by-step explanation:

Sum of all the angles of a triangle=180°      

Value of 1 angle=40°

Sum of the other 2 angles=(180-40)°=140°

Difference of the two angles=30°

Therefore, the larger angle={(140+30)÷2}°=(170÷2)° degrees=85°        

Answer 2

Answer:

Let the difference of two angle be x and y

x-y=30°

x=30°+y.......eqn(i)

Now,

40°+30°+y=180°

y=180°-70°

y=110°

Again,

Putting value of y in eqn(i)

x=30°+y

x=30°+110°

x=140°

So, the larger of other two angle value is 110° and 140°