Question

One angles of an isosceles triangle is 110° ,find the remaining two angles​

Answer 1

Answer:

$let \: the \: two \: numbers = x$

A/Q

$x + x + 110 = 180 \\ 2x = 180 - 110 \\ x = \frac{70}{2} = 45$

Answer 2

$\sf\star \: \underbrace\purple{Given-} \: \star$

• One of angles of an isosceles triangle is110°.

• $\triangle$ ABC is a isosceles triangle.

• AB = AC.

$\sf\star \: \underbrace\orange{To \: Find-} \: \star$

• Measure of angles B & C.

$\sf\star \: \underbrace\red{Diagram-} \: \star$

$\setlength{\unitlength}{1.2cm}\begin{picture}(0,0)\linethickness{0.4mm}\qbezier(1, 0)(1,0)(3,3)\qbezier(5,0)(5,0)(3,3)\qbezier(5,0)(5,0)(1,0)\qbezier(3.5,2.3)(3,2)(2.5,2.3)\qbezier(1.5,0.8)(1.8,0.5)(1.8, 0)\qbezier(4,0)(4.2,0.7)(4.5,0.7)\put(1.8, 0.5){\sf x}\put(2.8, 1.8){ \sf 110^{\circ} }\put(2.9, 3.1){\sf A}\put(0.7, - 0.3){\sf B}\put(5, - 0.3){\sf C}\end{picture}$

$\sf\star \: \underbrace\blue{Solution-} \: \star$

$\bf{In \: triangle \: ABC,}$

$\bf{AB = BC ... (Angles \: opposite \: to \: equal \: sides \: are \: equal)}$

$\bf{Thus,}$

$\bf\angle \: c \: = \bf\angle \: b$

$\bf{Now,}$

$\bf\angle \: a + \bf\angle \: b \: + \: \bf\angle \: c = 180 \: ...(Angle \: sum \: property \: of \: triangle$

$\bf\implies{110 + x + x = 180}$

$\bf\implies{2 x = 180 - 110}$

$\bf\implies{2x = 70}$

$\sf\star \: \underbrace{x = 35} \: \star$

Hence,

• Remaining two angles measures 35°.