One antifreeze solution is 36% alchol and another is 20% alcohol. How much of each mixture should be added to make 40L of a solution that is 30% alchol?
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Answer:
We know :-
3O% ALCOHOL = 4OL
ON FIRST SANITIZER :-
6% ALCOHOL SHOULD BE DECREASED
36% = 6\1OO X 4O
= 2.4
42.4L = 36% ( 42.4 -2.4) = 4OL
ON SECOND SANITIZER:-
2O% = 2O\1OO X 4O
= 8
2O% = 32L ( 32 + 8 = 4OL)
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