Question

one atmosphere is numerically equal to​

Answer 1

Answer:

101,325 pascals or newton's

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Answer 2

Answer:

One atmosphere is numerically equal to

${10}^{6} dyne \: {cm}^{ - 2} or \: {10}^{5} pa$

Explanation :

1 atm=101325 Pa or 10^5 Pa

1 dyne cm ^-2 = 0.1 Pa

Now,

1 atm = (101325 × 1 dyne cm^-2) / 0.1 Pa

= 1013250 dyne cm^-2

Hence , 1 atm = 10^ 6 dyne cm ^-2 .

• The force an air column exerts on a given area is known as atmospheric pressure, commonly referred to as barometric pressure.
• The average atmospheric pressure at sea level at a temperature of 15 degrees Celsius (59 degrees Fahrenheit) is referred to as an atmosphere (atm).

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