Chemistry, asked by pranav3145, 26 days ago

One atmosphere is numerically equal to aproximately a) 10^6 dynes cm b) 10^2 dynes cm^-2 c) 10^4 dynes cm ^-2 d) 10^8 dynes cm^-2

Answers

Answered by vaibhavkumarhp20

1

Explanation:

Correct option isA

10^6dynecm^−2

Pdyne/cm^2 =P atm ×1.01325×10^6

P atm =1

then P dynecm^2 =1.01325×10^6

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