Question

one atom of an element weighs 1.79 2 into 10 power minus 22the atomic weight of element is​

Answer 1

Answer:  108 g/mol.

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles .

Given:

1 atom of an element weighs equal to $1.792\times 10^{-22}$

Thus  to know the atomic weight , we need to find the weight of avogadro's number $6.023\times 10^{23}$ of particles .

Thus 1 atom of an element weighs= $1.792\times 10^{-22}$

$6.023\times 10^{23}$ atoms of a element weigh=$\frac{1.792\times 10^{-22}{1}\times 6.023\times 10^{23}=108 g/mol$

The atomic weight of element is​ 108 g/mol.

Answer 2

Answer:

By avagadros law one atom contains 6.022×10^23 moles

Explanation:

Hence, 1.792 ×10^-22×6.022 ×10^23=108