one bag contain 4 balls with numbers 2,4,5,7 and second bag contains 7 balls with numbers 1,2,3,4,5,6,7, if one of the two bags selected at random and then a ball is drawn.find the probability that drawn ball bears the odd number.
Answers
15/28 is the probability that drawn ball bears the odd number
Step-by-step explanation:
one bag contain 4 balls with numbers 2,4,5,7
odd numbers 5 , 7
Probability of odd numbers = 2/4 = 1/2
Second bag containing 7 balls with number 1,2,3,4,5,6,7,
odd numbers 1 , 3 , 5 , 7
Probability of odd numbers = 4/7
Probability of each bag = 1/2
probability that drawn ball bears the odd number. = (1/2)(1/2) + (1/2)(4/7)
= 1/4 + 2/7
= (7 + 8)/28
= 15/28
15/28 is the probability that drawn ball bears the odd number
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