One bag contains 5 black and 3 white balls. Another bag contains 4 black and 5 white balls. One ball is drawn from each bag. Find the probability that they are of different color?
Answers
Answer: 37/72
Step-by-step explanation: This is a tricky question, but I will try to explain
Probability shows the relationship between two variables in the form of ratio, percentage or proportion where there the chances of occurrence of one variable is expressed in terms of the other variable which is usually sample space.
The sample space is the total number of outcomes
The sample space for the first bag is 8.
Let A be the event of getting black balls
P(A) = 5/8
Let B be the event of getting white balls
P(B) = 3/8
The sample space for the second bag is 9.
Let C be the event of getting black balls
P(C) = 4/9
Let D be the event of getting white balls
P(D) = 5/9
Now, Let E be the event that ball drawn from each bag will be different
P(E) = P(A) P(D) + P(B) P(C)
= (5/8) (5/9) + (3/8) (4/9)
= 37/72
Answer:
5/17
Step-by-step explanation:
