Question

one ball is picked up randomly from a bag containing 8 yellow 7 blue and 6 black balls. what is the probability that it is neither yellow nor black?

Answer 1

$\textbf {Hey there, here is the solution.}$

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Total number of balls = 8 + 7 + 6 = 21

Total number of not yellow or black balls = 7

P(Neither yellow or black) = 7/21 = 1/3

Answer : The probability is 1/3

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⭐$\textbf {Cheers}$⭐

Answer 2

$\fbox { heya !! }$

Here is Your Answer

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Given Data :- Bag contains

8 → Yellow balls

7 → Blue balls

6 → Black balls

Total number of Balls = 8 + 7 + 6 = 21

= 21

$\fbox { probability = \frac {No .of favourable outcomes} { no.of possible outcomes }}$

Question :- probability of getting a ball neither black nor yellow

This means That the ball picked should not be black and yellow

This means $\textbf { ball picked up is Blue}$


Here

Number of favourable outcomes = 7 ( blue balls )

Number of possible outcomes = 21 (total number of Balls )

$probability = \frac{7}{21} = \frac{1}{3}$

$\fbox { Answer : \frac {1} {3}}$

Glad if Helped....!!!

(^^)