One beam of electrons moves at right angles to a magnetic field. The force on these electrons is 4.9 × 10-14 newtons. A second beam travels at the same speed, but at a 30° angle with the magnetic field. What force is on these electrons?
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hello,
we know that F=qvBsinθ where q is charge v is velocity B is magnetic field and sinθ is the angle at which it is projected or rotates about
we know that force on 1st beam of electrons is 4.9×10⁻¹⁴N with angle of 90°
now,in the same speed and same magnetic field but with angle 30°
for 1st-F=qvBsin90° sin90° is 1 ∴F= qvB = 4.9×10⁻¹⁴
for 2nd-F=qvBsin30° sin30° is 1/2 ∴F=qvB1/2 =4.9×10⁻¹⁴N/2
=2.45×10⁻¹⁴N
hope this helps if u like it please mark it as brainliest
we know that F=qvBsinθ where q is charge v is velocity B is magnetic field and sinθ is the angle at which it is projected or rotates about
we know that force on 1st beam of electrons is 4.9×10⁻¹⁴N with angle of 90°
now,in the same speed and same magnetic field but with angle 30°
for 1st-F=qvBsin90° sin90° is 1 ∴F= qvB = 4.9×10⁻¹⁴
for 2nd-F=qvBsin30° sin30° is 1/2 ∴F=qvB1/2 =4.9×10⁻¹⁴N/2
=2.45×10⁻¹⁴N
hope this helps if u like it please mark it as brainliest
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