Question

One box contains 5 blue and 4 green marbles. Another box contains 7 blue and 9 green marbles. A marble is transferred from the first box to the second box and then a marble is drawn from the second box. Then find the probability that the marble drawn is blue.
Options

4/9

5/9

7/18

11/18

Answer 1

Answer:

4/7=40 this is the best,

5/9=80

Answer 2

The probability that the drawn marble from another box is blue is $\frac{4}{9}$.

Step-by-step explanation:

Given:

• One box contains 5 blue and 4 green marbles.
• Another box contains 7 blue and 9 green marbles.
• A marble is transferred from the first box to the second box and then a marble is drawn from the second box.

The probability that the transferred marble from one box is blue is $\frac{5}{9}$.

The probability that the transferred marble from one box is green is $\frac{4}{9}$.

The probability that the drawn marble from another box is blue is given by

$\rightarrow \: \frac{5}{9} \times \frac{8}{17} + \frac{4}{9} \times \frac{7}{17} \\ \rightarrow \: \frac{40 + 28}{9 \times 17} \\ \rightarrow \: \frac{68}{9 \times 17} \\ \rightarrow \: \frac{4}{9}$

The probability that the drawn marble from another box is blue is $\frac{4}{9}$.