One boy can eat 100 chocolates in half a minute, and another can eat half as many in twice the length of time. how many chocolates can both boys eat in 15 seconds?
Answers
And another boy eats half chocolates = 100/2 in 1 minute
Therefore the sum of the chocolates that can be eaten by the boys in 1 min are 200 + 50 = 250
So in 15 minutes they can eat 250 x 15 = 3750 chocolates
Given:
The number of chocolates eaten by a boy in 1/2 minute=100
The number of chocolates eaten by another boy in 1 minute=50
To find:
The number of chocolates eaten by both boys in 15 seconds
Solution:
The number of chocolates eaten by both boys in 15 seconds is 62.5.
We can find the number by following the given process-
We know that the number of chocolates eaten by both the boys is given.
The number of chocolates eaten by a boy in 1/2 minute or 30 seconds=100
The number of chocolates eaten by another boy in 1 minute or 60 seconds=50
So, we will calculate the number of chocolates eaten by both of them in 15 seconds.
The number of chocolates eaten by the first boy in 15 seconds=15×100/30
=50
The number of chocolates eaten by the other boy in 15 seconds=15×50/60
=12.5
Now, the total number of chocolate eaten=Number of chocolate eaten by the first boy+number of chocolates eaten by the other boy
On putting the values, we get
=50+12.5
=62.5 chocolates
Therefore, the number of chocolates eaten by both boys in 15 seconds is 62.5.