Question

One brother says of his younger brother: “Two years ago, I was three times as old as my brother was. In three years’ time, I will be twice as old as my brother.” How old are they each now?​

Answer 1

$\huge\color{black}\boxed{\colorbox{cyan}{Answer}}\downarrow$

$ \blue{ \implies} $ One way to solve this math riddle is to use even numbers: The older brother will be twice as old as his younger brother in three years’ time. This immediately rules out the older brother currently being 8, 11, and 14, so he must be 17, and the younger brother 7. Two years ago, they were 15 and 5 respectively, and in three years’ time, they will be 20 and 10.

hope this helps you!

Answer 2

Answer:

Let y is my age and x is my brother age now

2 years ago,

my age= y-2

brother age=x-2

According to condition my age was thrice the age of brother so

3(brothers age)= my age

3(x-2)=y-2

after evaluating y=3x-4

Now,

after 3 year from present ( Second case)

my age = y+3

brothers age = x+3

According to condition my age will be twice the age of brother so

2(brothers age)= my age

2(x+3)=y+3

after evaluation

2x=(y-3)

now put here value from 1st case of y=3x-4

2x=(3x-4–3)

x=7 and y=17

So my age is 17 and my brother age is 7 in present.

Check

2 years ago my age was 15 and my brother age was 5 so (3*5=15)

and same as 3 years later i will be 20 and he will be 10 which is (10*2=20).