One brother says of his younger brother: “Two years ago, I was three times as old as my brother was. In three years’ time, I will be twice as old as my brother.” How old are they each now?
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Answer:
Let consider x and y is the current age and y is the brother.
3 year before:
3(x-3)=(y-3)
3 year after
2(x+3)=(y+3)
After solving the above equation you get the present age of both.
X=9 year's old and Y is 21 years old.
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