One car moving on straight road covers one third of the distance with 20km/hr and the rest with 60km/hr.the avg speed is?
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Answered by
656
Assuming the total distance to be 3x.
Time taken by the car to cover one-third of the distance = x/20
Time taken to cover two-thirds of the distance by the car = 2x/60
= x/30 Total time taken by the car
= x/20 + x/30 equals to 5x/60 which is x/12
Average speed obtained= (Total distance travelled)/(Total time taken)
= (3x)/(x/12) = 36 kilometre/hour
Time taken by the car to cover one-third of the distance = x/20
Time taken to cover two-thirds of the distance by the car = 2x/60
= x/30 Total time taken by the car
= x/20 + x/30 equals to 5x/60 which is x/12
Average speed obtained= (Total distance travelled)/(Total time taken)
= (3x)/(x/12) = 36 kilometre/hour
Answered by
39
Ans:36km/h
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