One car travels 40. meters due east in 5.0 seconds, and a second car travels 64 meters due west in 8.0 seconds. During their periods of travel,the cars definitely had the same
Answers
Answer:
The cars definitely had the same SPEED, not velocity.
Explanation:
The answer might be a little tricky here. The average SPEED of both cars is 8 m/s. So your answer would be that the cars definitely had the same SPEED, not velocity. This is because velocity is direction-aware, and the cars are not going in the same direction. They do still share the same speed however, just not in the same direction.
During the period of traveling, the two cars had the same speed.
Given: the distance traveled by car 1, d₁ = 40 m
the time taken by car 1, t₁ = 5 s
the distance traveled by car 2, d₂ = 64 m
the time taken by car 2, t₂ = 8 s
To Find: speed of car 1, s₁.
speed of car 2, s₂.
Solution:
To calculate the speed of cars the formula used:
- speed = distance traveled/ time taken
- s = d / t
Applying the above formula for car 1:
s₁ = d₁ / t₁
= 40 / 5
= 8
s₁ = 8 m/s
For car 2:
s₂ = d₂ / t₂
= 64 / 8
= 8
s₂ = 8 m/s
On equating equations 1 and 2 :
s₁ = s₂
Hence, it can be concluded that during their period of traveling, the cars definitely had the same speed.