Question

One card is drawn from a pack of 52 cards each of 52 card is being equally likely to be drawn find probability:
1. Card drawn is king
2. Card drawn is red and king
3.Card drawn is black either red or a king
4.Card drawn is black

Answer 1

Answer:

1 ....4/52= 1/13

2.... 28/52

3...8-52/52

4... 24/52

Answer 2

Answer:

Out of 52 cards, one card can be drawn in 52 ways.

So, total number of elementary events = 52

(a) There are 26 red cards, including two red kings, in a pack of 52 playing cards. Also, there are 4 kings, two red and two black. Therefore, card drawn will be either a red card or a king if it is any one of 28 cards (26 red cards and 2 black kings).

So, favorable number of elementary events = 28

Hence, required probability =

(b) There are 6 red face cards 3 each from diamonds and hearts. Out of these 6 red face cards one card can be chosen in 6 ways.

So, favorable number of elementary events = 6

Hence, required probability =

(c) There are two suits of black cards, viz., spades and clubs. Each suit contains one card bearing number 10.

So, favorable number of elementary events = 2

Hence, required probability =2/52=1/26