Question

one card is drawn from a well shuffled deck of 52 cards. Calculate the probability that the cards will (a) be an ace and (b) not be an ace??
​

Answer 1

Answer:

this is the answer so mark as brainliest

Answer 2

${\huge{\sf{\bold{\boxed{\color{Pink}{Answer}}}}}}$

Well-shuffling ensures equally likely outcomes.

(i) Card drawn is an ace

There are 4 aces in a deck.

Let E be the event ‘the card is an ace’.

The number of outcomes favourable to E = n(E) = 4

The number of possible outcomes = Total number of cards = n(S) = 52

Therefore, P(E) = n(E)/n(S) = 4/52 = 1/13

(ii) Card drawn is not an ace

Let F be the event ‘card drawn is not an ace’.

The number of outcomes favourable to the event F = n(F) = 52 – 4 = 48

Therefore, P(F) = n(F)/n(S) = 48/52 = 12/13

Hope it's Helpful.....:)